Sqr
Returns a square root of a number
Syntax
`
Declare Function Sqr ( ByVal number As Double ) As Double
`
Usage
`
result = Sqr( number )
`
Parameters
`number`
the number (greater than or equal to zero)
Return Value
Returns the square root of the argument `number`.
If `number` equals zero, `Sqr` returns zero (`0.0`).
If `number` is less than zero, `Sqr` returns a special value representing "not defined", printing like "`NaN`" or `"IND"`, exact text is platform dependent.
Description
This is the same as raising the argument `number` to the one-half power: `y = x ^ (1/2)` . The required `number` argument can be any valid numeric expression greater than or equal zero.
If a `LongInt` or `ULongInt` is passed to `Sqr`, it may be converted to `Double` precision first. For numbers over `2^52`, this will cause a very small loss of precision. Without making any assumptions about the rounding method, the maximum error due to this will be `Sqr(2^64) - Sqr(2^64-2^12)`, which is about `4.8e-7`. However this may cause erroneous results if the floor or ceiling of this value is taken, and the result of this may be out by `1`, particularly for square numbers and numbers that are close by.
Example
`
'' Example of Sqr function: Pythagorean theorem
Dim As Single a, b
Print "Pythagorean theorem, right-angled triangle"
Print
Input "Please enter one leg side length: ", a
Input "Please enter the other leg side length: ", b
Print
Print "The hypotenuse has a length of: " & Sqr( a * a + b * b )
`
The output would look like:

    Pythagorean theorem, right-angled triangle

    Please enter one leg side length: 1.5
    Please enter the other leg side length: 2

    The hypotenuse has a length of: 2.5

Differences from QB

- None

See also

- `Operator ^ (Exponentiate)`
- Arithmetic Operators